-5x^2+168x-840=0

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Solution for -5x^2+168x-840=0 equation:



-5x^2+168x-840=0
a = -5; b = 168; c = -840;
Δ = b2-4ac
Δ = 1682-4·(-5)·(-840)
Δ = 11424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{11424}=\sqrt{16*714}=\sqrt{16}*\sqrt{714}=4\sqrt{714}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(168)-4\sqrt{714}}{2*-5}=\frac{-168-4\sqrt{714}}{-10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(168)+4\sqrt{714}}{2*-5}=\frac{-168+4\sqrt{714}}{-10} $

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